Rigidbody.AddExplosionForce

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public void AddExplosionForce (float explosionForce, Vector3 explosionPosition, float explosionRadius, float upwardsModifier= 0.0f, ForceMode mode= ForceMode.Force));

Parameters

explosionForceThe force of the explosion (which may be modified by distance).
explosionPositionThe centre of the sphere within which the explosion has its effect.
explosionRadiusThe radius of the sphere within which the explosion has its effect.
upwardsModifierAdjustment to the apparent position of the explosion to make it seem to lift objects.
modeThe method used to apply the force to its targets.

Description

Применение силы к твердому телу имитирует эффект взрыва. Сила взрыва убывает линейно относительно расстояния до твердого тела.

The explosion is modelled as a sphere with a certain centre position and radius in world space; normally, anything outside the sphere is not affected by the explosion and the force decreases in proportion to distance from the centre. However, if a value of zero is passed for the radius then the full force will be applied regardless of how far the centre is from the rigidbody.

This function applies a force to the object at the point on the surface of the rigidbody that is closest to explosionPosition. The force acts along the direction from explosionPosition to the surface point on the rigidbody. If explosionPosition is inside the rigidbody, or the rigidbody has no active colliders, then the center of mass is used instead of the closest point on the surface.

The magnitude of the force depends on the distance between explosionPosition and the point where the force was applied. As the distance between explosionPosition and the force point increases, the actual applied force decreases.

The vertical direction of the force can be modified using upwardsModifier. If this parameter is greater than zero, the force is applied at the point on the surface of the Rigidbody that is closest to explosionPosition but shifted along the y-axis by negative upwardsModifier. Using this parameter, you can make the explosion appear to throw objects up into the air, which can give a more dramatic effect rather than a simple outward force. Force can be applied only to an active rigidbody. If a GameObject is inactive, AddExplosionForce has no effect.

using UnityEngine;
using System.Collections;

// Applies an explosion force to all nearby rigidbodies public class ExampleClass : MonoBehaviour { public float radius = 5.0F; public float power = 10.0F;

void Start() { Vector3 explosionPos = transform.position; Collider[] colliders = Physics.OverlapSphere(explosionPos, radius); foreach (Collider hit in colliders) { Rigidbody rb = hit.GetComponent<Rigidbody>();

if (rb != null) rb.AddExplosionForce(power, explosionPos, radius, 3.0F); } } }
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