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  • C#

PBXProject.GetPBXProjectPath

Declaration

public static string GetPBXProjectPath(string buildPath);

Parameters

buildPath The project build path.

Returns

string The path to the PBX project file. This path can be opened later using the ReadFromFile function.

Description

Returns the path to PBX project in the given Unity build path.

This function can only be used for Unity-generated projects.

Note: On VisionOS and macOS platforms this will return BUILDPATH/Unity-iPhone.xcodeproj/project.pbxproj, which isn't correct. Its not recommended to use this method when developing for visionOS or macOS.

using UnityEditor;
using System.IO;
using UnityEditor.Callbacks;
using UnityEditor.iOS.Xcode;

public class Sample_GetPBXProjectPath { [PostProcessBuild] public static void OnPostprocessBuild(BuildTarget buildTarget, string pathToBuiltProject) {

// Stop processing if build target is not iOS if (buildTarget != BuildTarget.iOS) return;

// Initialize PBXProject by using GetPBXProjectPath to create PBXProject object string projectPath = PBXProject.GetPBXProjectPath(pathToBuiltProject); PBXProject pbxProject = new PBXProject(); pbxProject.ReadFromFile(projectPath);

// Get the GUID for the UnityFramework using it's name string unityFrameworkGuid = pbxProject.TargetGuidByName("UnityFramework");

// The unityFrameworkGuid can be used later to specify the UnityFramework as the target when manipulating the pbxproj file pbxProject.AddFrameworkToProject(unityFrameworkGuid, "Security.framework", false); pbxProject.SetBuildProperty(unityFrameworkGuid, "ENABLE_BITCODE", "NO"); // Apply changes to the pbxproj file pbxProject.WriteToFile(projectPath); } }

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